37-4 The Relativity of Velocities#
Prompts
In Galilean relativity, if a particle has speed \(u'\) in frame \(S'\) and \(S'\) moves at \(v\) relative to \(S\), the speed in \(S\) is \(u = u' + v\). Why does this fail when \(u'\) or \(v\) is close to \(c\)?
Derive the relativistic velocity addition formula \(u = (u' + v)/(1 + u'v/c^2)\) from the Lorentz transformation. (Hint: \(u = \Delta x/\Delta t\), \(u' = \Delta x'/\Delta t'\).)
Show that if \(u' = c\) (e.g., a light beam in \(S'\)), then \(u = c\) in \(S\)—the speed of light is invariant.
A spaceship moves at \(0.9c\) relative to Earth. It fires a probe at \(0.9c\) relative to the ship (in the same direction). What is the probe’s speed relative to Earth? Compare with the naive \(1.8c\).
When is the relativistic formula approximately equal to \(u = u' + v\)?
Lecture Notes#
Overview#
Velocities do not add simply in relativity. The Galilean rule \(u = u' + v\) fails when speeds approach \(c\).
The relativistic velocity transformation gives the correct relation between a particle’s velocity as measured in two inertial frames in relative motion.
A key consequence: if a particle (or light) has speed \(c\) in one frame, it has speed \(c\) in all frames—the speed of light is invariant.
The formula follows directly from the Lorentz transformation.
Relativistic velocity addition#
Consider frames \(S\) and \(S'\) with \(S'\) moving at speed \(v\) in the \(+x\) direction relative to \(S\). A particle moves with constant velocity parallel to the \(x\)-axis. In \(S'\) its speed is \(u' = \Delta x'/\Delta t'\); in \(S\) its speed is \(u = \Delta x/\Delta t\).
From the Lorentz transformation (difference form):
Dividing \(\Delta x\) by \(\Delta t\):
Inverse (from \(S\) to \(S'\)): interchange \(u\) and \(u'\), replace \(v\) by \(-v\):
Key properties#
Invariance of \(c\). If \(u' = c\) (e.g., a light signal in \(S'\)):
The speed of light is the same in all inertial frames—consistent with the second postulate.
Galilean limit. For \(u' \ll c\) and \(v \ll c\), the denominator \(1 + u'v/c^2 \approx 1\), so \(u \approx u' + v\). The relativistic formula reduces to the familiar Galilean addition.
No speed exceeds \(c\). For any \(u' < c\) and \(v < c\), one can show \(u < c\). Velocities “add” in such a way that \(c\) is never exceeded.
Sign convention
\(v\) is the velocity of \(S'\) relative to \(S\) (positive when \(S'\) moves in \(+x\)). For motion in the negative \(x\) direction, use negative values of \(u'\), \(u\), or \(v\) as appropriate.
Example: ship and probe
Ship moves at \(v = 0.9c\) relative to Earth. Probe fired at \(u' = 0.9c\) relative to ship (same direction). Speed relative to Earth: \(u = (0.9c + 0.9c)/(1 + 0.81) = 1.8c/1.81 \approx 0.994c\). Galilean addition would give \(1.8c\) (impossible); relativity keeps \(u < c\).
Summary#
Velocity transformation: \(u = (u' + v)/(1 + u'v/c^2)\); inverse \(u' = (u - v)/(1 - uv/c^2)\).
Derived from the Lorentz transformation; valid for motion along the common \(x\)-axis.
\(c\) is invariant: if \(u' = c\) then \(u = c\). No velocity exceeds \(c\).
Galilean limit: \(u \approx u' + v\) when \(u', v \ll c\).