17-5 Sources of Musical Sound#

Prompts

  • For a pipe open at both ends, where are the nodes and antinodes? Sketch the fundamental and first two harmonics. What is \(\lambda\) for the fundamental?

  • For a pipe closed at one end and open at the other, where are the node and antinode? Why are only odd harmonics (\(n = 1, 3, 5, \ldots\)) possible?

  • Write the resonant frequencies for (a) open-open and (b) open-closed pipes in terms of \(L\), \(v\), and \(n\).

  • A flute (open-open) and a clarinet (open-closed) are the same length. Which has the lower fundamental frequency? By what factor?

  • Two instruments play the same note (same fundamental). Why do they sound different? What is timbre?

Lecture Notes#

Overview#

  • Musical instruments produce sound through standing waves—resonance when the wavelength matches the geometry.

  • Pipes (flute, organ, clarinet): standing waves in air columns. Strings (guitar, piano): standing waves on stretched strings (section 16-7).

  • Two pipe types: open at both ends (all harmonics) and open at one end, closed at the other (odd harmonics only).

  • Timbre (tone color) comes from the mix of harmonics—different instruments playing the same note sound different.


Standing waves in pipes: boundary conditions#

Sound waves reflect at pipe ends. The boundary condition determines whether the end is a node (zero displacement) or antinode (maximum displacement):

End type

Displacement

Analogy

Closed

Node

Fixed end of string

Open

Antinode

Free end of string

  • At a closed end, air cannot move longitudinally → node.

  • At an open end, air moves freely → antinode (slightly beyond the physical end).


Pipe open at both ends#

Antinodes at both ends. The simplest pattern has one node in the middle:

(131)#\[ \lambda = \frac{2L}{n}, \quad f = \frac{nv}{2L}, \quad n = 1, 2, 3, \ldots \]
  • Fundamental (\(n = 1\)): \(\lambda = 2L\), one node at center.

  • All harmonics present: \(n = 1, 2, 3, \ldots\) (odd and even).

Distance between nodes

For standing waves, the distance between adjacent nodes is \(\lambda/2\). So a pipe of length \(L\) fits \(n\) half-wavelengths when \(\lambda = 2L/n\).


Pipe closed at one end (open-closed)#

Antinode at open end, node at closed end. The simplest pattern has \(\lambda = 4L\) (quarter-wavelength fits in the pipe):

(132)#\[ \lambda = \frac{4L}{n}, \quad f = \frac{nv}{4L}, \quad n = 1, 3, 5, \ldots \]
  • Fundamental (\(n = 1\)): \(\lambda = 4L\).

  • Only odd harmonics: \(n = 1, 3, 5, \ldots\)—even \(n\) would require an antinode at the closed end, which is impossible.

Pipe type

Fundamental \(\lambda\)

Resonant frequencies

Open-open

\(2L\)

\(f = nv/(2L)\), \(n = 1, 2, 3, \ldots\)

Open-closed

\(4L\)

\(f = nv/(4L)\), \(n = 1, 3, 5, \ldots\)


Musical instruments#

  • Strings: guitar, piano, violin—standing waves on strings (section 16-7).

  • Air columns: flute (open-open), clarinet (open-closed), pipe organ, saxophone.

  • Shorter instrument → higher fundamental frequency.

Flute vs clarinet

Same length \(L\): flute (open-open) has \(f_1 = v/(2L)\); clarinet (open-closed) has \(f_1 = v/(4L)\). The clarinet’s fundamental is half the flute’s—it sounds an octave lower.


Timbre#

Real sounds are a superposition of the fundamental and higher harmonics. Two instruments playing the same note have the same fundamental frequency but different harmonic content (relative amplitudes of \(n = 1, 2, 3, \ldots\)). That mix is timbre—why a flute and oboe sound different even on the same pitch.


Summary#

  • Closed end → node; open end → antinode.

  • Open-open: \(f = nv/(2L)\), \(n = 1, 2, 3, \ldots\); all harmonics.

  • Open-closed: \(f = nv/(4L)\), \(n = 1, 3, 5, \ldots\); odd harmonics only.

  • Timbre: different harmonic mix → different tone color for the same pitch.