36-1 Single-Slit Diffraction#
Prompts
What is a single-slit diffraction pattern? How does it differ from the pattern in Young’s double-slit experiment? What lies at the center?
Explain the zone method for finding the first minimum: why do we divide the slit into two zones? What path length difference gives destructive interference?
Write the condition for all minima in single-slit diffraction. How does the angle of the first minimum depend on slit width \(a\) and wavelength \(\lambda\)?
If we narrow the slit or increase the wavelength, does the diffraction pattern expand or contract? Why?
What is the Fresnel bright spot? Why did Poisson’s prediction (a bright spot in the shadow of a sphere) support the wave theory of light?
Lecture Notes#
Overview#
Single-slit diffraction: Light passing through a narrow slit produces a diffraction pattern—a broad central maximum, narrower secondary maxima, and minima in between. This is interference of Huygens wavelets from different points within the slit.
Minima occur when \(a\sin\theta = m\lambda\) (\(m = 1, 2, 3, \ldots\)). Maxima lie approximately halfway between adjacent minima.
Narrower slit \(\Rightarrow\) more diffraction (wider pattern). Diffraction limits geometrical optics when apertures are comparable to \(\lambda\).
Diffraction and the diffraction pattern#
When waves pass through an aperture or past an edge comparable in size to the wavelength, they spread (diffract) and interfere with themselves. The result is a diffraction pattern.
For a long narrow slit of width \(a\) illuminated by monochromatic light:
Central maximum: broad, intense. All Huygens wavelets from the slit travel nearly the same distance to the center \(\Rightarrow\) in phase.
Secondary maxima: narrower, less intense, on both sides.
Minima: dark fringes between the maxima.
Geometrical optics would predict a sharp slit image; the actual pattern shows that light is a wave.
Diffraction vs. double-slit interference
Double-slit (Ch. 35): two coherent sources; path length difference \(d\sin\theta\) determines bright/dark. Single-slit: many sources across the slit; we find minima by pairing zones that cancel.
Locating the minima: the zone method#
To find the first minimum, divide the slit into two zones of width \(a/2\) each. Consider rays from corresponding points in the two zones (e.g., top of each zone) reaching a point \(P_1\) at angle \(\theta\).
Path length difference between the two rays: \((a/2)\sin\theta\) (from the geometry when \(D \gg a\)).
For destructive interference, this difference must be \(\lambda/2\)—so the two rays cancel. Every such pair cancels; the whole slit contributes zero at \(P_1\):
Second minimum: Divide the slit into four zones. Pairs from adjacent zones cancel when \((a/4)\sin\theta = \lambda/2\) \(\Rightarrow\) \(a\sin\theta = 2\lambda\).
All minima:
(\(m = 0\) gives \(\theta = 0\), the center—a maximum, not a minimum.)
Maxima: Approximately halfway between minima (e.g., first side maximum near \(a\sin\theta \approx 1.5\lambda\)). Exact positions require the intensity analysis of section 36-2.
Slit width and wavelength#
From \(a\sin\theta = m\lambda\):
Change |
Effect on pattern |
|---|---|
Narrower slit (\(a \downarrow\)) |
\(\theta\) increases \(\Rightarrow\) pattern expands |
Longer wavelength (\(\lambda \uparrow\)) |
\(\theta\) increases \(\Rightarrow\) pattern expands |
When \(a = \lambda\), the first minimum is at \(\theta = 90°\)—the central maximum fills the entire screen. Diffraction is strongest when the aperture is on the order of the wavelength.
Distance on the screen#
When \(\theta\) is small, \(\sin\theta \approx \theta\). The distance \(y\) from the center to the \(m\)th minimum is
where \(D\) is the slit-to-screen distance. The width of the central maximum (distance between first minima) is \(\approx 2D\lambda/a\).
Poll: Central maximum width—effect of slit width
A single slit of width \(a\) produces a central diffraction maximum of width \(l\). You decrease the slit width to \(a/2\). What is the new width of the central maximum?
(A) \(l/2\)
(B) \(l\)
(C) \(2l\)
(D) \(4l\)
Poll: Central maximum—effect of wavelength
Same slit. You switch from 600 nm to 500 nm light. How does the width of the central bright fringe change?
(A) Increases
(B) Decreases
(C) Stays the same
(D) Depends on the slit width
The Fresnel bright spot#
In 1819, Poisson (a Newtonian) argued that Fresnel’s wave theory predicted a bright spot at the center of the shadow of a sphere—seemingly absurd. The experiment showed the spot was there. This Fresnel bright spot supported the wave theory: light diffracts around the edge and interferes constructively at the center of the shadow.
Example: First minimum angle
White light through a slit. First minimum for red (\(\lambda = 650\) nm) at \(\theta = 15°\): \(a = \lambda/\sin\theta = 650\,\text{nm}/\sin 15° \approx 2.5\,\mu\text{m}\). The slit must be very narrow—a few wavelengths.
Summary#
Single-slit diffraction: central maximum + secondary maxima separated by minima.
Minima: \(a\sin\theta = m\lambda\), \(m = 1, 2, 3, \ldots\) (zone method: pair canceling waves).
Narrower slit or longer \(\lambda\) \(\Rightarrow\) pattern expands.
Fresnel bright spot: bright spot in shadow of disk/sphere; supports wave theory.