19-1 Avogadro’s Number#

Prompts

  • What is Avogadro’s number \(N_A\)? How many molecules are in one mole?

  • Write the relation between number of moles \(n\), number of molecules \(N\), and \(N_A\). How do you find \(N\) from the mass of a sample?

  • The molar mass of water (H\(_2\)O) is 18 g/mol. How many molecules are in 18 g of water?

  • How is molar mass \(M\) related to the mass \(m\) of one molecule?

Lecture Notes#

Overview#

  • Kinetic theory connects macroscopic quantities (pressure, temperature) to microscopic ones (molecular speed, kinetic energy).

  • Avogadro’s number \(N_A\) is the number of atoms or molecules in one mole of a substance.

  • Molar mass \(M\) is the mass of one mole. Relations: \(n = N/N_A = m_{\text{sam}}/M\) and \(M = m\,N_A\) (where \(m\) = mass per molecule).


Avogadro’s number and the mole#

(168)#\[ N_A = 6.02 \times 10^{23}\;\text{mol}^{-1} \quad \text{(Avogadro's number)} \]
  • One mole of any substance contains \(N_A\) elementary units (atoms or molecules).

  • The mole is an SI base unit, defined via the carbon-12 standard (12 g of \(^{12}\)C = 1 mol).


Number of moles and mass#

(169)#\[ n = \frac{N}{N_A} = \frac{m_{\text{sam}}}{M} \]
  • \(n\): number of moles.

  • \(N\): number of molecules.

  • \(m_{\text{sam}}\): mass of the sample.

  • \(M\): molar mass (mass per mole).

Molar mass and molecular mass:

(170)#\[ M = m\,N_A \]

where \(m\) is the mass of one molecule. So \(M\) (g/mol) = mass per molecule × molecules per mole.


Summary#

  • \(N_A = 6.02 \times 10^{23}\) mol\(^{-1}\)—molecules per mole.

  • \(n = N/N_A = m_{\text{sam}}/M\)—moles from molecule count or mass.

  • \(M = m\,N_A\)—molar mass from molecular mass.