17-8 Supersonic Speeds, Shock Waves#

Prompts

  • When a source moves at the speed of sound (\(v_S = v\)), what happens to the Doppler formula? Why does it break down?

  • For \(v_S > v\), sketch how spherical wavefronts bunch. What shape do they form in 2D? In 3D?

  • Derive the Mach cone half-angle: \(\sin\theta = v/v_S\). (Hint: consider a wavefront emitted at \(t = 0\) and the source position at time \(t\).)

  • What is the Mach number? An aircraft at Mach 2 travels how many times the speed of sound?

  • What causes a sonic boom? Why does a bullwhip crack?

Lecture Notes#

Overview#

  • When a source moves faster than sound (\(v_S > v\)), the Doppler formulas (section 17-7) no longer apply—they predict infinite or undefined frequencies when \(v_S \geq v\).

  • Wavefronts bunch into a cone called the Mach cone. A shock wave travels along this surface—a sharp pressure change.

  • The sonic boom is the audible burst when the shock wave passes an observer.


Why the Doppler formula breaks down#

For \(v_S = v\) (source at the speed of sound), the denominator \(v - v_S\) in the Doppler formula becomes zero → infinite detected frequency. The source keeps pace with its own wavefronts; they pile up at the source.

For \(v_S > v\), the source outruns its wavefronts. Spherical wavefronts emitted at different times overlap and form an envelope—the Mach cone.


The Mach cone#

When \(v_S > v\), wavefronts emitted at successive positions bunch along a V-shaped envelope (2D) or cone (3D). The half-angle \(\theta\) of the Mach cone satisfies

(140)#\[ \sin\theta = \frac{v}{v_S} \]

Derivation: In time \(t\), a wavefront expands to radius \(vt\); the source moves \(v_S t\). The cone is tangent to the wavefront—the tangent makes angle \(\theta\) with the direction of motion, so \(\sin\theta = (vt)/(v_S t) = v/v_S\).


Mach number#

The Mach number is

(141)#\[ M = \frac{v_S}{v} \]
  • Mach 1: \(v_S = v\) (speed of sound).

  • Mach 2: \(v_S = 2v\) (twice the speed of sound).

  • In terms of \(M\): \(\sin\theta = 1/M\) → faster source → narrower cone.


Shock wave and sonic boom#

A shock wave exists along the surface of the Mach cone—air pressure rises sharply, then drops below normal, then returns. When this surface passes an observer, the result is a sonic boom: a loud burst of sound.

Example

Explanation

Supersonic jet

Shock cone sweeps along the ground as the jet flies

Rifle bullet

Tip can exceed speed of sound → small sonic boom

Bullwhip crack

Tip accelerates past \(v\) → localized sonic boom

Subsonic vs supersonic

Subsonic (\(v_S < v\)): wavefronts spread ahead of the source; Doppler formula applies. Supersonic (\(v_S > v\)): wavefronts bunch into a cone; shock wave forms.


Summary#

  • \(v_S \geq v\): Doppler formula breaks down; wavefronts bunch into a cone.

  • \(\sin\theta = v/v_S = 1/M\)—Mach cone half-angle.

  • Mach number \(M = v_S/v\).

  • Shock wave along the cone; sonic boom when it passes an observer.