17-8 Supersonic Speeds, Shock Waves#
Prompts
When a source moves at the speed of sound (\(v_S = v\)), what happens to the Doppler formula? Why does it break down?
For \(v_S > v\), sketch how spherical wavefronts bunch. What shape do they form in 2D? In 3D?
Derive the Mach cone half-angle: \(\sin\theta = v/v_S\). (Hint: consider a wavefront emitted at \(t = 0\) and the source position at time \(t\).)
What is the Mach number? An aircraft at Mach 2 travels how many times the speed of sound?
What causes a sonic boom? Why does a bullwhip crack?
Lecture Notes#
Overview#
When a source moves faster than sound (\(v_S > v\)), the Doppler formulas (section 17-7) no longer apply—they predict infinite or undefined frequencies when \(v_S \geq v\).
Wavefronts bunch into a cone called the Mach cone. A shock wave travels along this surface—a sharp pressure change.
The sonic boom is the audible burst when the shock wave passes an observer.
Why the Doppler formula breaks down#
For \(v_S = v\) (source at the speed of sound), the denominator \(v - v_S\) in the Doppler formula becomes zero → infinite detected frequency. The source keeps pace with its own wavefronts; they pile up at the source.
For \(v_S > v\), the source outruns its wavefronts. Spherical wavefronts emitted at different times overlap and form an envelope—the Mach cone.
The Mach cone#
When \(v_S > v\), wavefronts emitted at successive positions bunch along a V-shaped envelope (2D) or cone (3D). The half-angle \(\theta\) of the Mach cone satisfies
Derivation: In time \(t\), a wavefront expands to radius \(vt\); the source moves \(v_S t\). The cone is tangent to the wavefront—the tangent makes angle \(\theta\) with the direction of motion, so \(\sin\theta = (vt)/(v_S t) = v/v_S\).
Mach number#
The Mach number is
Mach 1: \(v_S = v\) (speed of sound).
Mach 2: \(v_S = 2v\) (twice the speed of sound).
In terms of \(M\): \(\sin\theta = 1/M\) → faster source → narrower cone.
Shock wave and sonic boom#
A shock wave exists along the surface of the Mach cone—air pressure rises sharply, then drops below normal, then returns. When this surface passes an observer, the result is a sonic boom: a loud burst of sound.
Example |
Explanation |
|---|---|
Supersonic jet |
Shock cone sweeps along the ground as the jet flies |
Rifle bullet |
Tip can exceed speed of sound → small sonic boom |
Bullwhip crack |
Tip accelerates past \(v\) → localized sonic boom |
Subsonic vs supersonic
Subsonic (\(v_S < v\)): wavefronts spread ahead of the source; Doppler formula applies. Supersonic (\(v_S > v\)): wavefronts bunch into a cone; shock wave forms.
Poll: Mach cone
An aircraft flies at Mach 2. What is the half-angle \(\theta\) of its Mach cone? (\(\sin 30° = 0.5\))
(A) 30°
(B) 45°
(C) 60°
Summary#
\(v_S \geq v\): Doppler formula breaks down; wavefronts bunch into a cone.
\(\sin\theta = v/v_S = 1/M\)—Mach cone half-angle.
Mach number \(M = v_S/v\).
Shock wave along the cone; sonic boom when it passes an observer.